11x^2+7x=106

Solution for 11x^2+7x=106 equation:

11x^2+7x=106

We move all terms to the left:

11x^2+7x-(106)=0

a = 11; b = 7; c = -106;
Δ = b2-4ac
Δ = 72-4·11·(-106)
Δ = 4713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{4713}}{2*11}=\frac{-7-\sqrt{4713}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{4713}}{2*11}=\frac{-7+\sqrt{4713}}{22}
$